for-loops in python (basic)

Question

Is it possible to make a two functions with seperate for-loops but that the second function gets what the first one did? I have a very simple example:

a = [1,2,3,4]

def func():
    for i in a:
        if i == 1:
            continue

def func2():
        func()
        for i in a:
            print(i)

print(func2())

The problem with the second function is that it doesnt "get" what the first function does. How could I fix this? I want the second function to get the first one so that I can continue on with statements.

This question is a bit unclear, at least to me. Can you explain what output you're trying to get? — Mureinik
– Mureinik, Commented Nov 30, 2020 at 22:08
What exactly did the first function do that you expect to be visible to the caller? — chepner
– chepner, Commented Nov 30, 2020 at 22:09

wjandrea · Accepted Answer · 2020-11-30 22:09:45Z

2

To pass information from one function to another, the first function needs to return it.

def func(a):
    r = []
    for i in a:
        if i == 1:
            continue
        r.append(i)
    return r

def func2(a):
    r = func(a)
    for i in r:
        print(i)

func2([1, 2, 3, 4])

edited Nov 30, 2020 at 22:09

wjandrea

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answered Nov 30, 2020 at 22:08

Samwise

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1 Comment

wjandrea Over a year ago

FWIW, you can rewrite func as a comprehension: return [i for i in a if i != 1]

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