Iterator function python

Question

im trying to figure out how to make an iterable function in python, since im new to it i would appreciate any help, here is my code :

cra_initial = cra_func(a,b,c)
def cra(cra_initial):
   cra_annum = (cra_initial /7) *365
   'and so on some code contains a, b, c variables above'
   cra_adjusted = cra_func(a,b,c)

as you see in the last line of the code cra_adjusted is using the same function cra_initial in the first line is using, i want to get the result of cra_adjusted and use it as an argument in cra function for like 20 times iterable

This question is about tail recursion and not about iterators. — Aplet123
– Aplet123, Commented Dec 28, 2020 at 13:04
im asking if it could be done by iteration, if not what kind of recursion — Abdulla Osama
– Abdulla Osama, Commented Dec 28, 2020 at 13:07

yourson · Accepted Answer · 2020-12-29 12:43:46Z

1

I have found out an easy way of doing it here its

cra_initial = cra_func(a,b,c)
def cra(cra_initial):
    for i in range (1,20):
       cra_annum = (cra_initial /7) *365
      'and so on some code contains a, b, c variables above'

       cra_adjusted = cra_func(a,b,c)
       cra_initial = cra_adjusted

Its more effective

edited Dec 29, 2020 at 12:43

yourson

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answered Dec 28, 2020 at 14:37

Abdulla Osama

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Comments

Sabito · Accepted Answer · 2021-01-31 04:06:30Z

0

I think this code would help you.

i=1

def cra_func(a,b,c):
    return (a+b+c)

def cra(cra_initial):
    global i
    cra_annum = (cra_initial /7) *365
    print(cra_annum)
    a,b,c=1,2,3
    cra_adjusted = cra_func(a,b,c)
    i+=1
# This condition will make cra() func run 20 times
    if i<21:
        cra(cra_adjusted)

if __name__=='__main__':
    a,b,c=1,2,3
    cra_initial = cra_func(a,b,c)
    cra(cra_initial)

Rest you can edit accordingly..

edited Jan 31, 2021 at 4:06

Sabito

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answered Dec 28, 2020 at 14:30

yourson

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2 Comments

yourson Over a year ago

Variables must be used accordingly

Sabito Over a year ago

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