Java - Open a URL from a string

Question

I plan on having a bunch of URLs specified in strings.xml, eg:

<string name="a1_url">https://en.wikipedia.org</string>

I would like to be able to open a URL (eg string name "a1_url") from an activity, but can't figure out how to reference the string name in Uri.parse. This current code works fine when you hardcode the URL:

Intent i2=new Intent(Intent.ACTION_VIEW, Uri.parse("https://en.wikipedia.org"));
                startActivity(i2);

My overall goal is to have many URLs as strings and the app will choose one for you at random, eg a1_url or a233_url.

You can get the value from string.xml with getString() method of Context. developer.android.com/reference/android/content/… — Pemassi
– Pemassi, Commented Jan 3, 2021 at 8:23
please don't include the android studio tag just because you're using it to develop your app, only use it if you're asking about a feature of the ide specifically — a_local_nobody
– a_local_nobody, Commented Jan 3, 2021 at 8:34

AmrDeveloper · Accepted Answer · 2021-01-03 08:32:51Z

1

First, you need to load the string value from resources XML

String url = getString(R.string.a1_url);

Then use it in your intent

answered Jan 3, 2021 at 8:32

AmrDeveloper

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1 Comment

KERR Over a year ago

Perfect, here's the end result: String url = getString(R.string.a1_url); Intent i2=new Intent(Intent.ACTION_VIEW, Uri.parse(url));

user13146129 · Accepted Answer · 2021-01-03 08:38:08Z

0

Intent i2=new Intent(Intent.ACTION_VIEW, Uri.parse(R.string.a1_url));
            startActivity(i2);

answered Jan 3, 2021 at 8:38

user13146129

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