Extract 15 digit string from text using regex (re.findall) in python [duplicate]

Question

My input is--

Text = "My name is Alex , house no - 254456845 with mobile no. +91-11-22558845 and my account no. is - AB12569BF214558."

Now I want to use regex (re.findall) on my input text and get the expected output.

Expected Output= ( it contains both digits and alphabet and is always of length = 15 )

[ "AB12569BF214558" ]

please help

The duplicate link given is not, IMHO, enough because it doesn't include the exact regex logic/approach which is needed here. — Tim Biegeleisen
– Tim Biegeleisen, Commented Jan 5, 2021 at 6:40

Tim Biegeleisen · Accepted Answer · 2021-01-05 05:36:48Z

0

You should be using the following regex pattern:

\b[A-Z0-9]{15}\b

This will ensure that you match a string of uppercase/numbers which is exactly 15 characters in length. Sample script:

Text = "My name is Alex , house no - 254456845 with mobile no. +91-11-22558845 and my account no. is - AB12569BF214558."
matches = re.findall(r'\b[A-Z0-9]{15}\b', Text)
print(matches)

This prints:

['AB12569BF214558']

answered Jan 5, 2021 at 5:36

Tim Biegeleisen

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Matt Miguel · Accepted Answer · 2021-01-05 10:29:29Z

0

import re
results = re.findall('\\b[A-Z0-9]{15}\\b','''My name is Alex , house no - 254456845 with mobile no. +91-11-22558845 and my account no. is - AB12569BF214558.''')

edited Jan 5, 2021 at 10:29

answered Jan 5, 2021 at 5:34

Matt Miguel

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4 Comments

Lokesh Choraria Over a year ago

this solution gives me my expected output in this case, but when i use this code in other cases then i gives me all the strings that have length 15 or more, i just want that string length should be strictly 15 only and not other string with length more than 15 should be given in output.

Matt Miguel Over a year ago

The {15} means exactly 15 characters. Fifteen or more would be {15,}

Matt Miguel Over a year ago

Oh I think I understand what you mean. The result is only 15 characters, but it is part of a longer string. Adding the '\b' at the start and end per Tim B's answer takes care of that.

10 Rep Over a year ago

@MukulKant Please don't mark code only answers like this. Otherwise you will get banned from reviewing.

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