Check background of item in table web using Selenium with Python

Question

pic 1

pic 2

I have a table as pic 1. I need to find one invalid cell (valid: green-background, invalid: red-background). If they're all valid as picture, I must press to back previous page I got script to get current page:

current_page =driver.find_element("//span[@class='currentPage']).get_attribute("innerText")

But I don't know how to loop through each cell of table to find which one valid or not to click or do other actions.

Thank your help in advance

Timeler · Accepted Answer · 2021-01-14 10:05:57Z

1

you can get all elements with a certain class/css selector/whatever by using driver.find_elements_by_whatever_you_want . then you can loop through the elements by using a simple for i in elements loop and get the attribute for every element. you can then say what happens if the cell is valid or not.

answered Jan 14, 2021 at 10:05

Timeler

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2 Comments

Scorpisces Over a year ago

Thanks @Timeler, I get a list of element through valid_ext_list = driver.find_elements("xpath...") but how could I click on any element inside that list?

Timeler Over a year ago

well you can simply do "for i in valid_ext_list: i.click()

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