Creating multiple empty files in a loop python

Just place your call to open inside a loop:

for i in range(1, 11):
    with open(f'test{i}.txt', 'w'):
        pass

range is used to generate a sequence of integers; it's start inclusive and end exclusive so range(1,11) yields integers 1 to 10. The f string within open provides a nice way to place variables in strings.

Here's how to do what you want to do in a single line:

for i in range(10): open(f'/tmp/test{i+1}.text', 'w').close()

If you want to create files when they don't exist, but not blow away the contents of any file that already exists, just use a instead of w.

It's simple and easy in python.

#counting starts from 0
for i in range(10):
    i+=1
    with open(f"test{i}.txt","w"):
        pass

F-String in Python

Your style is ok, but needs a bit of modification in your code. I corrected your code. Please see below:

import os
def createFiles():
    lab3 = '/home/student/Lab3'
    lab3 = 'F:\ProjectWorks\Python\pythonCore\PythonPractice\MyFolder\MyFolder2'
    # Before creation of files
    dir_list = os.listdir(lab3)
    print("List of directories before creating files")
    print(dir_list)
    print()

    os.chdir(lab3)

    for i in range(1, 11):
        with open(f'test{i}.txt', 'w'):
            pass
    # After creation of files
    dir_list = os.listdir(lab3)
    print("Directory and files after file creation: ")
    print(dir_list)

createFiles()

What you could do is;

files = 10
for file_name in range(files):
     file = open(‘test’+str(file_name)+'.txt', ‘w’)
     file.close()

This will make 10 blank files