Cannot click on login button in Python

Question

I am trying to automate login to this website. While Python adds username and password, it couldn't click on login button "Inloggen". I do not get any error but it does not click on login button.

here is my code:

from selenium import webdriver
from webdriver_manager.chrome import ChromeDriverManager
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC


driver = webdriver.Chrome(ChromeDriverManager().install())

url = "https://portal.spryngsms.com/login?redirect=%2F"
username = "cosmos"
password = "12345"

driver.get(url)

driver.get('https://portal.spryngsms.com/login?redirect=%2F')

WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, 
"//span[text()='Gebruikersnaam']//following::div[1]//input"))).send_keys("cosmos")
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, 
"//span[text()='Wachtwoord']//following::div[1]//input"))).send_keys("12345")

driver.find_element_by_xpath("//span[text()='Wachtwoord']//following::div[1]//input").click()

Samsul Islam · Accepted Answer · 2021-02-15 13:58:26Z

1

Use css selector instead of xpath. It's work for me

driver.find_element_by_css_selector("#app > div.application--wrap > div.tw-flex.tw-w-full.tw-pr-8 > div > div > div > div > div > section > form > footer > div.form__footer-bottom.form__footer-bottom--login > div > button").click()

answered Feb 15, 2021 at 13:58

Samsul Islam

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Comments

yaro · Accepted Answer · 2021-02-15 14:06:06Z

0

I recommend you to check the selector for button first, seems like you are trying to click onto password input instead of button.

As @Sumsul Islam said, there is no need to use xpath in this case, each element is accessible by css selectors just fine.

But also it's quite enough to use this selectors instead of full css path:

//login
input[type="text"]

//password
input[type="password"]

//button
.form__footer button

answered Feb 15, 2021 at 14:06

yaro

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Comments

maanijou · Accepted Answer · 2021-02-15 14:12:46Z

Here's an answer that works pretty good with xpath:

from selenium import webdriver
from webdriver_manager.chrome import ChromeDriverManager
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC


driver = webdriver.Chrome(ChromeDriverManager().install())

url = "https://portal.spryngsms.com/login?redirect=%2F"
username = "cosmos"
password = "12345"

driver.get(url)

driver.get('https://portal.spryngsms.com/login?redirect=%2F')

WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, 
"//span[text()='Gebruikersnaam']//following::div[1]//input"))).send_keys("cosmos")
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, 
"//span[text()='Wachtwoord']//following::div[1]//input"))).send_keys("12345")

driver.find_element_by_xpath("/html/body/div[1]/div[3]/div[1]/div/div/div/div/div/section/form/footer/div[2]/div/button").click()

Whether you're using Firefox or chrome, You can use inspect the element and right-click on your desired element and select copy > copy xpath

You can use copy CSS selectors as well:

driver.find_element_by_css_selector(".form__footer-bottom > div:nth-child(1) > button:nth-child(1)").click()

KunduK · Accepted Answer · 2021-02-15 14:26:19Z

0

Use WebDriverWait() and wait for element_to_be_clickable() and following locator.

Xpath:

WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH,"//button[contains(.,'Inloggen')]"))).click()

Css Selector:

WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR,"div[class='mi-button__Container']> .button--normal.icon.button--normal-secondary.button--mi"))).click()

answered Feb 15, 2021 at 14:26

KunduK

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