How to get the list specific multiple links in Selenium python

Question

I need to get list of links from a webpage it has href="/example/*" it doesn't have any specific class name or id.

elems = driver.find_elements_by_xpath("//a[@href]")
for elem in elems:
    print(elem.get_attribute("href"))

Right now, I'm getting all the links in the page.

Tarun Lalwani · Accepted Answer · 2021-03-12 05:05:01Z

1

You can either do the filter in the xpath itself (recommended approach)

elems = driver.find_elements_by_xpath("//a[contains(@href,'/example/')]")
for elem in elems:
    print(elem.get_attribute("href"))

or you can fetch and then filter

elems = driver.find_elements_by_xpath("//a[@href]")
for elem in elems:
    href = elem.get_attribute("href")
    if '/example/' in href:
       print(href)

edited Mar 12, 2021 at 5:05

answered Mar 12, 2021 at 4:10

Tarun Lalwani

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2 Comments

Strawbewy Over a year ago

how about if i wanted to locate it also in specific div? for an example <div class="content"> ... #list is here ... </div>

Tarun Lalwani Over a year ago

Then you would use //div[@class='content']//a[contains(@href, '/example/')]'

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