I need to replace some characters in a line of a logfile.
One Part of this logfile is defined as:
(sha1: b2ac534797bceb683ee5db85fcd4bbb885c4a205, md5: bb4fd7d270c523bb5d1c6c18e9b42801, sha256: e5b9090d2f0efd5aa99102aae223b4e346c6c8229d4931d08bbb5d1d43146cfd)
I want to replace the whole string with a simple ;
ForEach {$_ -replace "\' (SHA-1:^[a-z][0-9]$ , MD5:^[a-z][0-9]$ , SHA-256:^[a-z][0-9]$ ",";"}
But that doesn't work. Get the message, the pattern is not valid.
The target string can be described as (...) where ... is a group consisting of <algoName>: <hash> and an optional trailing sequence , , repeated 3 times:
$replaced = Get-Content path\to\file.log |ForEach-Object {
$_ -replace '\(((sha|md)\d+: [a-f0-9]+(, )?)+\)', ';'
}
$replaced |Set-Content path\to\output.txt
If the log file is relatively small (eg. KBs instead of MBs), you can also apply -replace directly to output from Get-Content:
@(Get-Content path\to\file.log) -replace '\(((sha|md)\d+: [a-f0-9]+(, )?)+\)', ';' |Set-Content path\to\output.txt
3 times, but the regex simply uses +, which can be confusing (I looked in vain for {3})). Since line breaks don't matter here, you can even do Get-Content -Raw, which will be substantially faster (though then requires -NoNewLine when writing the result to a file).