How to get the message value of a nested exception in Python?

Question

I have an exception that looks like this:

exc = ProtocolError('Connection Aborted', BadStatusLine('No status line received'))

how can I access the No status line received part?

Here's the example situation:

def some_function():
    raise ProtocolError('Connection Aborted', BadStatusLine('No status line received'))

def some_other_function():
    try:
        some_function()
    except Exception as exc:
        if exc.message:
            details = exc.message
        else:
            details = exc

In the code above I'm trying to check if the returned exception has a message and if so I'm supposed to write it into the database, however when I call the exc.message it returns an empty string, and when I call exc it returns:

bson.errors.InvalidDocument: cannot encode object: ProtocolError('Connection Aborted', BadStatusLine('No status linereceived',)), of type: <class 'urllib3.exceptions.ProtocolError'>

so I cant write it into the database since its a type Exception not string, what I need to do is to see if the returned Exception has another nested Exception in it and get it's message.

@ZainUlAbidin type: <class 'urllib3.exceptions.ProtocolError'> — SLDem
– SLDem, Commented Jun 1, 2021 at 11:30
can you provide the code to reproduce the problem . so that it can be quicly answered and solved — Zain Ul Abidin
– Zain Ul Abidin, Commented Jun 1, 2021 at 11:33
ProtocolError is not defined . .from where you are using or importing this function? urllib3? — Zain Ul Abidin
– Zain Ul Abidin, Commented Jun 1, 2021 at 11:53

Zain Ul Abidin · Accepted Answer · 2021-06-01 12:29:48Z

1

I wasn't able to find the exact optimal way to fetch the inner message or exception but for quick assistance i wrote a utility function which by using regular expressions will return you inner exceptions or messages complete code is following

from urllib3.exceptions import ProtocolError
from http.client import BadStatusLine
import re

def FetchInnerExceptions(exc):
    result = []
    messages = str(exc).split(',')
    for msg in messages:
        m = re.search('''(?<=')\s*[^']+?\s*(?=')''', msg)
        if m is not None or m != '':
            result.append(m.group().strip())
    return result

def some_function():
    raise ProtocolError('Connection Aborted', BadStatusLine('No status line received'))

def some_other_function():
    try:
        some_function()
    except Exception as exc:
        e = FetchInnerExceptions(exc)
        print(e) #dumps all array or use index e[1] for your required message

some_other_function()

answered Jun 1, 2021 at 12:29

Zain Ul Abidin

2,7601 gold badge23 silver badges38 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

SLDem Over a year ago

Thank you mate, I think I made it work, i just used details = str(exc) in the last line and grabbed the whole record for the database, but I will check out your solution and maybe use it if that doesn't work :)

Zain Ul Abidin Over a year ago

ok just in case if it worked then don't forget to mark this as accepted to help others

Collectives™ on Stack Overflow

How to get the message value of a nested exception in Python?

1 Answer 1

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related