how to use filter in javascript for an array of arrays object?

const filtered = OBJc.filter(obj => obj.array_.some(array1.includes))

Or with es6 destructuring:

const filtered = OBJc.filter({ array_ } => array_.some(array1.includes))

Basically you check each array_ element to see if it's included in array 1, and keep only those who satisfy this condition.

You want to filter, so lets filter.

OBJc.filter()

Now, you want to return true when your property has some value right?

OBJc.filter(value => {
  return value['array_'].includes(x)
})

But there are multiple ones, and you need to know if at least some those values are on your list

OBJc.filter(value => {
  return array1.some(arrV => value['array_'].includes(arrV));
})

Or if you like one liners:

OBJc.filter(value => array1.some(arrV => value['array_'].includes(arrV)));

Here's the solution:

var array1 = ['new_user', 'promotion']

JSONstr = [
    {"id": 1, "array_": ['promotion', 'test1']},
    {"id": 2, "array_": ['test444', 'test1']},
    {"id": 3, "array_": ['new_user', 'test1']}
]

const result = JSONstr.filter(obj => {
    let found = false;
    array1.forEach(elm => {
        if (obj.array_.includes(elm)) {
            found = true;
        }
    });
    if (found) {
        return true;
    }
});

console.log(result);

Here's one way if you like playing with booleans.

const reduceTruth = (a, b) => a || b;

const matches = JSONstr.filter(element => {
    return element.array_.map( x => array1.map(y => y == x).reduce(reduceTruth, false)).reduce(reduceTruth, false);
});