Sort array of arrays ( could not find duplicate for THIS instance ) [duplicate]

Question

I have an array for a timeline chart of Google Charts

So the array looks like follows

let data = [
    ['Outreach ICU Follow-up', '2021-01-25', 2021-02-01],
    ['Hospital Stay'         , '2021-01-01', '2021-03-01'],
    ['ICU Stay'              , '2021-01-02', '2021-01-25'],
    ['Outreach ICU Follow-up', '2021-02-20', '2021-03-01'],
    ['ICU Stay'              , '2021-02-01', '2021-02-20'],
]

I lined up the date to see the chronological order. I need to sort this by the first data ( element 1 )

Cant use this because its for objects I think.

let ass = data.sort((x,y)=>y.dlk_assess_order-x.dlk_assess_order);

And this one is futile as-well.

var data = data.sort(function(a, b) { return a - b; });

How does one sort and array like this please? Is there perhaps a lodash function?

what is dlk_assess_order? why not sort by exactly what you said x[1] and y[1]? — Jamiec
– Jamiec, Commented Jun 15, 2021 at 15:24
Rather than hoping for a perfect example to copy and paste, spend some time understanding what the code you've already found does, and you'll realise that what you want is a trivial modification. There are also lots of examples on MDN. — IMSoP
– IMSoP, Commented Jun 15, 2021 at 15:27

Det · Accepted Answer · 2022-10-07 18:30:41Z

1

As your question said, you simply sort by the element at position 1

let data = [
    ['Outreach ICU Follow-up', '2021-01-25', '2021-02-01'],
    ['Hospital Stay'         , '2021-01-01', '2021-03-01'],
    ['ICU Stay'              , '2021-01-02', '2021-01-25'],
    ['Outreach ICU Follow-up', '2021-02-20', '2021-03-01'],
    ['ICU Stay'              , '2021-02-01', '2021-02-20'],
]

const sorted = data.sort((a,b) => a[1] - b[1]);
console.log(sorted);

edited Oct 7, 2022 at 18:30

Det

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answered Jun 15, 2021 at 15:27

Jamiec

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