Validating array only integer number in PHP

Question

I want to validate an array so only integer number is allowed. I've tried some ways but still doesn't get the result I want.

I have array like this:

array(5) { 
   [0]=> string(3) "312" 
   [1]=> string(2) "41" 
   [2]=> string(2) "44" 
   [3]=> string(2) "22" 
   [4]=> string(2) "22" 
}

First I'm writing a code like this:

$total= $_POST["total"];
if (!preg_match ("/^[0-9]*$/", $total) ) {  
        $ErrMsg = "Only numeric value is allowed.";
        echo $ErrMsg;
}

I got an error that said only string allowed for !preg_match function, this is because $total is an array.

Next is I'm trying to convert $total to a string.

$total= $_POST["total"];
$stringTotal = implode(", ", $total);
    
    if (!preg_match ("/^[0-9]*$/", $total) ) {  
        $ErrMsg = "Only numeric value is allowed.";
        echo $ErrMsg;

The code above no longer give error, but the result still wrong. $total is a string so the result will false.

Is there's any way how to do it? Thank you

After you implode, the string contains commas and spaces, so it doesn't match the regexp. — Barmar
– Barmar, Commented Aug 3, 2021 at 14:41
implode('', $total) so no commas or spaces are included in the result. — kmoser
– kmoser, Commented Aug 3, 2021 at 14:48

Barmar · Accepted Answer · 2021-08-03 14:45:24Z

2

You can loop through the array.

foreach ($total as $num) {
    if (!preg_match("/^[0-9]*$/", $num) ) {  
        $ErrMsg = "Only numeric value is allowed.";
        echo $ErrMsg;
        break;
    }
}

Note also that your regular expression matches an empty string and treats it as an integer. If you don't want to include that, change * to +.

answered Aug 3, 2021 at 14:45

Barmar

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