I'm trying to pass variables from python script to bash, but not able to invoke the variable in bash.
clustername=sys.argv[1]
subprocess.check_call("/data/path/script.sh '%s'" % str(clustername), shell=True, stdout=subprocess.PIPE, universal_newlines=True)
And tried to print subprocess output, but was not able to print.
It is returning only code
Below is the bash script:
#!/bin/bash
clustername=$clustername # invoking from pythonscript
------
---Some logic -
---end
Firstly, in the bash file you are supposed to do:
#!/bin/bash
clustername=$1 # invoking from pythonscript
to get the command line arguments passed into the script.
Secondly, using check_call(), you will not be able to catch the output from the bash script. You will need to use subprocess.run() or subprocess.check_output() or something similar to achieve that.
You can try doing the following:
import sys
import subprocess
clustername=sys.argv[1]
print(subprocess.run(["/data/path/script.sh", str(clustername)], universal_newlines=True).stdout)
check_call() will only return the return code and not the stdout. You can also try check_output() if you want to see the output.
You can also do the following using check_output:
print(subprocess.check_output(["/data/path/script.sh", str(clustername)], universal_newlines=True))
Removed shell=True as suggested in the comments.
shell=True here, too. See also Actual meaning of shell=True in subprocessstdout= keyword argument, the default behavior is for the subprocess to print directly to standard output, outside of Python's view or control.
shell=True, I'm getting FileNotFoundError. Any idea why?shell=True, i.e. subprocess.run(["/data/path/script.sh", str(clustername)], ...)
script.sh?