Gson toJson returning string of JSON instead of JSON Object

Question

The Class that I'm using with toJson

class LoadUserDTO: Serializable {
    @SerializedName("userGuid")
    var userGuid: String? = null

    @SerializedName("userToken")
    var userToken: String? = null

    constructor(userGuid: String, userToken: String) {
        this.userGuid = userGuid
        this.userToken = userToken
    }
}

And the rest of the use:

val payload = LoadUserDTO(userGuid = user.guid!!, userToken = user.token!!)

val jsonPayload = Gson().toJson(payload)

this.socketService.socket.emit(EndpointsEnum.AppLoadUser, jsonPayload)

The jsonPayload should be a JSON Object. Instead, the entire thing is a String of what should be a JSON Object:

"{"userGuid":"...","userToken":"..."}"

When this is received by the server, it's not receiving a JSON Object as the Web UI or Swift App sends, but is instead just a String, not converted to a JSON Object.

What do you mean by a JSON object? what is your expected output compared to whats currently happening? How do you know it is sending a string? — DevWithZachary
– DevWithZachary, Commented Sep 6, 2021 at 15:55
@DevWithZachary I can set a breakpoint on the API endpoint. The data is a string, when it should be an object. When I do the same thing via the Web App its an object, also when I do it from the iOS App, it's an object. In this case it's sending across as a string. — smb
– smb, Commented Sep 6, 2021 at 17:35

Harsh Gupta · Accepted Answer · 2021-09-06 15:32:21Z

0

try this,

var jsonString = """{"id":1,"description":"Test"}""";
var testModel = gson.fromJson(jsonString, TestModel::class.java)

answered Sep 6, 2021 at 15:32

Harsh Gupta

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1 Comment

smb Over a year ago

I'm not looking to create a Java Object. I want an actual JSON Object sent over the wire instead of a string of the JSON Object.

Zahid Islam · Accepted Answer · 2021-09-06 16:55:00Z

0

Based on your requirement instead using Gson you may use String.format to achieve this by one line of code -

   // val payload = LoadUserDTO(userGuid = user.guid!!, userToken = user.token!!)
   // val jsonPayload = Gson().toJson(payload)
     val jsonPayload = String.format("\"{\"userGuid\": \"%s\"," + "\"userToken\": \"%s\"" + "}\"",user.guid,user.token)
   // Log.d("ZI",jsonPayload)

Output- example

"{"userGuid": "1234","userToken": "token000"}"

You may remove space after : while formatting string .

       val jsonPayload = String.format("\"{\"userGuid\":\"%s\"," + "\"userToken\":\"%s\"" + "}\"",user.guid,user.token)

Output-

"{"userGuid":"1234","userToken":"token000"}"

answered Sep 6, 2021 at 16:55

Zahid Islam

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1 Comment

smb Over a year ago

I have a lot of DTOs to setup as Objects. I definitely don't want to have to deal with string interpolation.

smb · Accepted Answer · 2021-09-06 18:01:52Z

0

I don't fully understand why yet, but this SO Question gave me the answer for it to work:

Send JSON data from in socket.io from android

val jsonPayload = Gson().toJson(payload)

val jsonObj = JSONObject(jsonPayload)

this.socketService.socket.emit(EndpointsEnum.AppLoadUser, jsonObj)

After making the jsonObj the server now has a properly formed JSON Object that it can work with.

answered Sep 6, 2021 at 18:01

smb

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