how to do sort in nested array javascript

Question

const res = [
  {
    _id: '5fbfa729fc46a415ce5503a6',
    first_name: 'AAA',
    last_name: 'BBBB',
    story: [
      {
        _id: '6136096f4255d84bcb4a7144',
        timestamp: 1630931311227,
        expire_at: '2021-09-06T12:28:31.227Z'
      }
    ]
  },
  {
    _id: '5fbf6f91aff7f3320a906547',
    first_name: 'DDD',
    last_name: 'FFFF',
    story: [
      {
        _id: '613609414255d84bcb4a7122',
        timestamp: 1630931265409,
        expire_at: '2021-09-06T12:27:45.409Z'
      }
    ]
  },
  {
    _id: '5fbfa748fc46a415ce5503a8',
    first_name: 'EEEE',
    last_name: 'FFFF',
    story: [
      {
        _id: '613609184255d84bcb4a710a',
        timestamp: 1630931224383,
        expire_at: '2021-09-06T12:27:04.383Z'
      },
      {
        _id: '613709f49223350dfdaec618',
        timestamp: 1630996980379,
        expire_at: '2021-09-07T06:43:00.379Z'
      },
      {
        _id: '61372d81c0a7ec4fa0f7a8e3',
        timestamp: 1631006081890,
        expire_at: '2021-09-07T09:14:41.890Z'
      }
    ]
  }
];

res.forEach((val, key) => {
  console.log('val', val.story);
  val.story.sort((a, b) =>
    a.timestamp > b.timestamp ? 1 : b.timestamp > a.timestamp ? -1 : 0
  );
});

I want to sort the object based on story's timestamp. who has posted latest story it should come first for example EEE has latest story post it should come at first place.

this object should be at first place after that others which false later this story and so on

{
    _id: '5fbfa748fc46a415ce5503a8',
    first_name: 'EEEE',
    last_name: 'FFFF',
    story: [....]
  }

1. Find out the most recent story in each object. 2. Copy its _id directly inside its parent object in a new key, for instance in most_recent_story. 3. Sort by most_recent_story. — Jeremy Thille
– Jeremy Thille, Commented Sep 7, 2021 at 9:55

Jay Li · Accepted Answer · 2021-09-07 10:20:35Z

const res = [ { _id: '5fbfa729fc46a415ce5503a6', first_name: 'AAA', last_name: 'BBBB', story: [ { _id: '6136096f4255d84bcb4a7144', timestamp: 1630931311227, expire_at: '2021-09-06T12:28:31.227Z' } ] }, { _id: '5fbf6f91aff7f3320a906547', first_name: 'DDD', last_name: 'FFFF', story: [ { _id: '613609414255d84bcb4a7122', timestamp: 1630931265409, expire_at: '2021-09-06T12:27:45.409Z' } ] }, { _id: '5fbfa748fc46a415ce5503a8', first_name: 'EEEE', last_name: 'FFFF', story: [ { _id: '613609184255d84bcb4a710a', timestamp: 1630931224383, expire_at: '2021-09-06T12:27:04.383Z' }, { _id: '613709f49223350dfdaec618', timestamp: 1630996980379, expire_at: '2021-09-07T06:43:00.379Z' }, { _id: '61372d81c0a7ec4fa0f7a8e3', timestamp: 1631006081890, expire_at: '2021-09-07T09:14:41.890Z' } ] } ];

function getEarliest(obj) {
    return obj.reduce((latest, e) => Math.max(latest, e.timestamp), 0)
}
const sorted = res.sort((a,b) => {
    return getEarliest(b.story) - getEarliest(a.story)
})
console.log(sorted)

this should work

vaira · Accepted Answer · 2021-09-07 10:09:05Z

const res = [
  {
    _id: '5fbfa729fc46a415ce5503a6',
    first_name: 'AAA',
    last_name: 'BBBB',
    story: [
      {
        _id: '6136096f4255d84bcb4a7144',
        timestamp: 1630931311227,
        expire_at: '2021-09-06T12:28:31.227Z'
      }
    ]
  },
  {
    _id: '5fbf6f91aff7f3320a906547',
    first_name: 'DDD',
    last_name: 'FFFF',
    story: [
      {
        _id: '613609414255d84bcb4a7122',
        timestamp: 1630931265409,
        expire_at: '2021-09-06T12:27:45.409Z'
      }
    ]
  },
  {
    _id: '5fbfa748fc46a415ce5503a8',
    first_name: 'EEEE',
    last_name: 'FFFF',
    story: [
      {
        _id: '613609184255d84bcb4a710a',
        timestamp: 1630931224383,
        expire_at: '2021-09-06T12:27:04.383Z'
      },
      {
        _id: '613709f49223350dfdaec618',
        timestamp: 1630996980379,
        expire_at: '2021-09-07T06:43:00.379Z'
      },
      {
        _id: '61372d81c0a7ec4fa0f7a8e3',
        timestamp: 1631006081890,
        expire_at: '2021-09-07T09:14:41.890Z'
      }
    ]
  }
];

let getRecent = (story) => Math.max(...story.map(s => s.timestamp))
  
  res.sort((a, b) =>{
as =getRecent(a.story);
bs =getRecent(b.story);
   return as > bs ? 1 : bs > as ? -1 : 0
});

console.log(res)

Mingze Li · Accepted Answer · 2021-09-07 10:21:59Z

0

First need to sort the nested story array, sort by big timestamp. Then sort the first layer array by comparing the timestamp of first element of each object

    res.forEach(function (element) {
        element.story.sort(function (a, b) {
            return (b.timestamp - a.timestamp)
        })
    })
    res.sort(function (a, b) {
        return (b.story[0].timestamp - a.story[0].timestamp)
    })
    console.log(res);

answered Sep 7, 2021 at 10:21

Mingze Li

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