Iteration of List Items using selenium in python

Question

I have a dropdown menu with 7 values and these 7 values are stored in the form of list items under unordered list as:

<ul class="rcbList" style="list-style:none;margin:0;padding:0;zoom:1;">
   <li class="rcbItem ">--Select--</li>
   <li class="rcbHovered ">PIPL-C1-BH-RILJM</li>
   <li class="rcbItem ">PIPL-C1-BH1-RILJM</li>
   <li class="rcbItem ">PIPL-C1-BH2-RILJM</li>
   <li class="rcbItem ">PIPL-C1-BH-RPLJM</li>
   <li class="rcbItem ">PIPL-C1-DHJ-RPLJM</li>
   <li class="rcbItem ">PIPL-C1-DHJ-RILJM</li>
</ul>

I want to click on each value of this dropdown menu using for loop with the help of selenium chromedriver in python.
Suppose I want to click on 2nd value PIPL-C1-BH-RILJM, I can do it as :

driver.find_element(By.XPATH,"//div[@id='ContentPlaceHolder1_rcmbCapacityTranch_DropDown']/div/ul/li[2]").click()

But to use it in the for loop, I have to do indexing on li tag. So, when I write as:

i=2
driver.find_element(By.XPATH,"//div[@id='ContentPlaceHolder1_rcmbCapacityTranch_DropDown']/div/ul/li['+str(i)+']").click()

It shows only --Select-- and does not select the 2nd value and same happens with other values of i.
I have also tried as:

i=2
driver.find_element(By.XPATH,"//div[@id='ContentPlaceHolder1_rcmbCapacityTranch_DropDown']/div/ul/li['"+str(i)+"']").click()

But --Select-- is selected again from the dropdown menu.
So, can anyone please help me to click on a particular value with indexing on li tag.
Any help would be appreciated.

pmadhu · Accepted Answer · 2021-11-02 14:23:13Z

1

Try like below once:

Collect all the li tag elements in a list and then iterate over them. Use find_elements for the same.

# This should highlight all the li tags - //div[@id='ContentPlaceHolder1_rcmbCapacityTranch_DropDown']/div/ul/li
options = driver.find_elements(By.XPATH,"//div[@id='ContentPlaceHolder1_rcmbCapacityTranch_DropDown']/div/ul/li")

# This should print 7
print(len(options))

# Start the loop from index 1 since the first option is "--Select--"
for i in range(1,len(options)):
    options[i].click()

answered Nov 2, 2021 at 14:23

pmadhu

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1 Comment

ankit Over a year ago

Thank you @pmadhu.

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