How to find this element in selenium python

To identify all of the similar elements and create a list you have to induce WebDriverWait for visibility_of_all_elements_located() and you can use either of the following Locator Strategies:

• Using CSS_SELECTOR:

  element_list = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, "a.do.do-task.btn.btn-sm.btn-primary.btn-block[data-task-id]")))
  

• Using XPATH:

  element_list = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//a[@class='do do-task btn btn-sm btn-primary btn-block' and @data-task-id]")))
  

Next, you can access each list item and invoke click() on each of them one by one.

• Note : You have to add the following imports :

  from selenium.webdriver.support.ui import WebDriverWait
  from selenium.webdriver.common.by import By
  from selenium.webdriver.support import expected_conditions as EC
  

If this css

a.do.do-task.btn.btn-sm.btn-primary.btn-block

represent them, then you can use the below code :

for a in driver.find_elements_by_css_selector("a.do.do-task.btn.btn-sm.btn-primary.btn-block"):
    a.click()

You may have to scroll to each element or put some delay before click, this depends on your use case and your automation strategy.