Cannot call a function using hooks in another function

Question

The logout function is used to log out a user by making an API call and deleting this user's information from LocalStorage and from the Redux store. This function therefore uses two hooks: useDispatch and useFetch (custom hook)

import {useDispatch} from 'react-redux'
import {disconnectUser} from 'store/authentication/authentication.slice'
import useFetch from 'api/useFetch'
import {routes} from 'routes/url'

type ResponseAPI = Record<string, never>

function logout(): void {
  const dispatch = useDispatch()

  const {call: disconnect} = useFetch<ResponseAPI>('auth/logout', {
    fetchOnLoad: false,
    method: 'POST',
  })

  disconnect()
    ?.then(() => {
      dispatch(disconnectUser())
      localStorage.removeItem('authenticated')
      localStorage.removeItem('decodedId')
      localStorage.removeItem('token')
      localStorage.removeItem('username')
      location.replace(routes.login)
    })
    .catch(error => Promise.reject(error))

  return
}

export default logout

I want to use this logout function in a button, as soon as the user clicks on the Logout button, it will be logged out.

const LogoutButton = (): JSX.Element => {
  return (
    <div className={styles.container}>
      <Button action={() => logout()}>Logout</Button>
    </div>
  )
}

export default LogoutButton

Unfortunately I get this error:

Error: Invalid hook call. Hooks can only be called inside of the body of a function component. This could happen for one of the following reasons:

You might have mismatching versions of React and the renderer (such as React DOM)

You might be breaking the Rules of Hooks

You might have more than one copy of React in the same app See https://reactjs.org/link/invalid-hook-call for tips about how to debug and fix this problem.

Do you have any ideas ? A big thank-you

The error message says it all: Hooks can only be called inside of the body of a function component, and function logout(): void is not a component — JSEvgeny
– JSEvgeny, Commented Jan 5, 2022 at 9:50

Rahul Sharma · Accepted Answer · 2022-01-05 09:56:45Z

logout is not a function it's the hook, and you can't use hook inside the function, because when you do action={() => logout()} you are wrapping hook inside the function. Which is not valid in the function component.

<Button action={logout}>Logout</Button>

Another Way

function useLogout() {
  const dispatch = useDispatch();

  const { call: disconnect } =
    useFetch <
    ResponseAPI >
    ("auth/logout",
    {
      fetchOnLoad: false,
      method: "POST",
    });

  const logout = () => {
    disconnect()
      ?.then(() => {
        dispatch(disconnectUser());
        localStorage.removeItem("authenticated");
        localStorage.removeItem("decodedId");
        localStorage.removeItem("token");
        localStorage.removeItem("username");
        location.replace(routes.login);
      })
      .catch((error) => Promise.reject(error));
  };

  return { logout };
}

// Component
const LogoutButton = (): JSX.Element => {
  const { logout } = useLogout();
  return (
    <div className={styles.container}>
      <Button action={() => logout()}>Logout</Button>
    </div>
  );
};

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