PHP "for" loop issue

Question

Simple question:

Why is this:

 for($k=1;$k<=10;$k+2) { }

giving an infinite loop? When I change $k+2 by $k++, it works fine.

How can I correct it? (I can't change the 10 for an impair number because I need this function to work either with a pair or impair value at that place)

@Shef $k will always be 1 in this case because $k is not updated — Jeffrey04
– Jeffrey04, Commented Aug 15, 2011 at 6:54
You are both right, just got up, such an early thought... :) — Shef
– Shef, Commented Aug 15, 2011 at 7:00

hakre · Accepted Answer · 2011-08-15 06:51:06Z

13

$k+2

This won't change $k's value, so it never get's higher than 10. Probably you meant:

$k+=2

Which will increase $k by two each time the expression get's evaluated (at the end of each for-loop).

answered Aug 15, 2011 at 6:51

hakre

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Luchian Grigore · Accepted Answer · 2011-08-15 06:51:16Z

4

 for($k=1;$k<=10; $k = $k+2) { }

or

 for($k=1;$k<=10; $k += 2) { }

answered Aug 15, 2011 at 6:51

Luchian Grigore

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Jeffrey04 · Accepted Answer · 2011-08-15 06:51:32Z

4

it is infinite loop because $k is not updated, try this instead

for($k = 1; $k <= 10; $k = $k + 2) {}

or

for($k = 1; $k <= 10; $k += 2) {}

Reference: PHP operators

answered Aug 15, 2011 at 6:51

Jeffrey04

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