Kotlin - Split string into new string

Question

I have a string that is a version number but I only need the last two digits of the string. I.e, 15.0.4571.1502 -> 4571.1502. I can't seem to figure out an efficient way to do this in Kotlin.

Code:

version = "15.0.4571.1502"

var buildOne = version.split(".").toTypedArray()[2]
var buildTwo = version.split(".").toTypedArray()[3]

var new = "$BuildOne"."$BuildTwo"

Error:

The expression cannot be a selector (occur after a dot)

Nitpick: I think you mean the last two components (or numbers) of the string. The last two digits of your example are 02. — gidds
– gidds, Commented Jan 26, 2022 at 23:38

Endzeit · Accepted Answer · 2022-01-26 20:00:21Z

7

You've written the dot outside of the string template, the following should work:

val new = "$BuildOne.$BuildTwo"

You can further simplify your solution, by making use of functions provided in the Kotlin standard library.

val version = "15.0.4571.1502"

val new = version
    .split(".")
    .takeLast(2)
    .joinToString(".")

answered Jan 26, 2022 at 20:00

Endzeit

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lukas.j · Accepted Answer · 2022-01-26 20:02:26Z

5

val version = "15.0.4571.1502"

val new = version.split('.').drop(2).joinToString(".")
// also possible:
// val new = version.split('.').takeLast(2).joinToString(".")

println(new)

answered Jan 26, 2022 at 20:02

lukas.j

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Comments

Arpit Shukla · Accepted Answer · 2022-01-27 02:59:07Z

5

Another possible solution using List destructuring:

val version = "15.0.4571.1502"
val (_, _, buildOne, buildTwo) = version.split(".")
val new = "$buildOne.$buildTwo"

answered Jan 27, 2022 at 2:59

Arpit Shukla

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