Defining dynamic function parameters in Typescript

Question

Given this:

type params = Parameters<(x: string, y:number)=>void>

In the pseudo code below how does one make fn to be (x: string, y:number)=>void, but using the params type?

type fn = (...params)=>void // type should be (x: string, y:number)=>void

akuiper · Accepted Answer · 2022-01-28 02:26:52Z

2

type fn = (...p: params)=>void

should work. Type the rest parameter with type params.

answered Jan 28, 2022 at 2:26

akuiper

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