How can you execute a method by giving its name, from another method that is in the same class with the called method? Like this:
class Class1:
def __init__(self):
pass
def func1(self, arg1):
# some code
def func2(self):
function = getattr(sys.modules[__name__], "func1") # apparently this does not work
Any suggestion?
how about getattr(self, "func1")? Also, avoid using the name function
For example:
>>> class C:
... def f1(self, arg1): print arg1
... def f2(self): return getattr(self, "f1")
...
>>> x=C()
>>> x.f2()(1)
1
getattr if you know the method you want -- just grab it.You should get the attribute from the class, not the module.
def func2(self):
method = getattr(self, "func1")
method("arg")
But you should also check that it's callable.
if callable(method):
method("arg")
This will avoid calling something that you didn't expect to get. You may want to raise your own exception here if it is not callable.
getattr is unnecessary when you know the name of the method. Also, why check if it's callable? Either it is (and should be if it's a method), or it will raise an exception -- which is the proper way to deal with an error.