Substrings or split methods in javascript

Question

I have a simple problem that I think I need help with. So, I have a function that accepts a string in this format

"1. Crowe, Velvet (LoC), 2. Hume, Eleanor (Ext), 4. Shigure, Rokurou (DmN), 10. Mayvin, Magilou (MgC)" without the quotation marks.

Basically, a list of person's names with rank number.

What I want is to split them such that I will get the ff result:

[
   "1. Crowe, Velvet (LoC)", 
   "2. Hume, Eleanor (Ext)", 
   "4. Shigure, Rokurou (DmN)",
   "10. Mayvin, Magilou (MgC)"
]

Is there a way to do that? I used split() method but it splits the string every time it sees an occurrence of the comma.

Is the format for each item always <number>. <text>, <text> (<text>)? — Nick Parsons
– Nick Parsons, Commented Mar 9, 2022 at 11:20
hacky and probably not best. split by ("),") and map result array and add ")" to each element. "1. Crowe, Velvet (LoC), 2. Hume, Eleanor (Ext), 4. Shigure, Rokurou (DmN), 10. Mayvin, Magilou (MgC)".split("),").map(el => el+")") — cmgchess
– cmgchess, Commented Mar 9, 2022 at 11:22

Nick Parsons · Accepted Answer · 2022-03-09 11:49:34Z

You could split using a regular expression /(?<=\)),\s/:

const str = "1. Crowe, Velvet (LoC), 2. Hume, Eleanor (Ext), 4. Shigure, Rokurou (DmN), 10. Mayvin, Magilou (MgC)";
const res = str.split(/(?<=\)),\s/);
console.log(res);

This will split on ), as suggested by cmgchess in the comments. The issue with splitting based on a string is that it removes some of the characters you want to keep. Instead, by using a regular expression, you can use (?<=\)) (here ?<= is called a positive lookbehind) to match and keep the ) in the resulting split element. The ,\s then splits based on a comma followed by a space (\s).

You could also use the following regex with .match() which is a little more robust, but may need to be updated depending on the text that can come after your number/rank:

/\d+\.\s\w+,\s\w+\s\(\w+\)/g

The above performs:

\d+\.: Will match one or more (+) digits followed by a dot
\s: Match a whitespace character
\w+,: Match one of more (+) word-characters (\w) followed by a comma ,
\s: Matches a space
\(\w+\): Match word characters surrounded by parentheses ( )
/g: Global flag to match the sequences for all occurrences in the string

const str = "1. Crowe, Velvet (LoC), 2. Hume, Eleanor (Ext), 4. Shigure, Rokurou (DmN), 10. Mayvin, Magilou (MgC)";
const res = str.match(/\d+\.\s\w+,\s\w+\s\(\w+\)/g);
console.log(res);

EzioMercer · Accepted Answer · 2022-03-09 11:38:10Z

0

Just a little improvement of @cmgchess's answer (add trim method to remove unnecessary spaces):

const getUsers = (str) => {
    const users = str.split('),').map(x => x.trim() + ')');
    users[users.length - 1] = users[users.length - 1].replace('))', ')');

    return users;
}

console.log(getUsers("1. Crowe, Velvet (LoC), 2. Hume, Eleanor (Ext), 4. Shigure, Rokurou (DmN), 10. Mayvin, Magilou (MgC)"));

edited Mar 9, 2022 at 11:38

answered Mar 9, 2022 at 11:33

EzioMercer

2,1492 gold badges11 silver badges30 bronze badges

3 Comments

cmgchess Over a year ago

actually my answer is not correct check the last element. maybe have to apply regex

Seven Over a year ago

Ah, there is an extra ")" at the last element. That was what @cmgchess meant by "the last element breaks".

EzioMercer Over a year ago

Sorry guys, now I replace extra )

Collectives™ on Stack Overflow

Substrings or split methods in javascript

2 Answers 2

Comments

3 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

3 Comments

Your Answer

Sign up or log in

Post as a guest

Related