Create variables dynamically with a For Loop Javascript

Question

The title plus the following example are self-explanatory of what I don't achieve :-) The idea is to replace something + counter in order to make it work.

      for (var counter = 1; counter <= 6; counter++) {
        var something + counter = $('element' + counter);
        (something + counter).removeAttribute('class');
      }

Why do you need to create a variable in the loop at all? Can you not just do $('element' + counter).removeAttribute('class');? — James Allardice
– James Allardice, Commented Aug 23, 2011 at 13:19

Eran Zimmerman Gonen · Accepted Answer · 2011-08-23 13:18:26Z

3

You could create an array, but much more simply:

  for (var counter = 1; counter <= 6; counter++) {
    $('element' + counter).removeAttribute('class');
  }

answered Aug 23, 2011 at 13:18

Eran Zimmerman Gonen

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Comments

jli · Accepted Answer · 2011-08-23 13:19:59Z

3

Just do:

for (var counter = 1; counter <= 6; counter++) {
    $('element' + counter).removeAttribute('class');
}

Unless you wanted to store it outside of the loop, in which case use an array.

answered Aug 23, 2011 at 13:19

jli

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Comments

Alex Turpin · Accepted Answer · 2011-08-23 13:18:49Z

2

Use an array.

var something = [];
for (var counter = 1; counter <= 6; counter++) {
    something[counter] = $('element' + counter);
    something[counter].removeAttribute('class');
}

answered Aug 23, 2011 at 13:18

Alex Turpin

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Comments

JConstantine · Accepted Answer · 2011-08-23 13:19:32Z

2

Why can't you just get rid of the var altogether??

for (var counter = 1; counter <= 6; counter++) {
    $('element' + counter).removeAttribute('class');
}

answered Aug 23, 2011 at 13:19

JConstantine

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Comments

Michael Sagalovich · Accepted Answer · 2011-08-23 13:22:03Z

0

  for (var counter = 1; counter <= 6; counter++) {
    window[something + counter] = $('element' + counter);
    window[something + counter].removeAttribute('class');
  }

after that there will be a set of fields in window object, named something1, something2 etc (if something == "something", of course)

answered Aug 23, 2011 at 13:22

Michael Sagalovich

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