count specific characters in a list of strings python

Question

Hi what I am trying to do is count the specific occurrences of the characters common to each string in the list below and print out each string and how many times the common characters appear example barack a appears 2 barack r appears 1 when I run my code it prints that each character appears 1

list1 = ['barack', 'obar?ma', '?america?', 'war', 'russia?', 'mak?er'] 

common = set.intersection(*map(set,list1))

new_list = list(common)

for i in list1:
    for a in new_list:
        if a in i:
            x = new_list.count(a)
            print([i] + [a])
            print(x)

Ukulele · Accepted Answer · 2022-04-07 10:19:05Z

1

Change x = new_list.count(a) to x = i.count(a). At the moment you are counting how many as in 'a'; you want to count how many as in barack.

The new code with this modification:

list1 = ['barack', 'obar?ma', '?america?', 'war', 'russia?', 'mak?er']

common = set.intersection(*map(set,list1))

new_list = list(common)

for i in list1:
    for a in new_list:
        if a in i:
            x = i.count(a)
            print([i] + [a])
            print(x)

prints this:

['barack', 'a']
2
['barack', 'r']
1
['obar?ma', 'a']
2
['obar?ma', 'r']
1
['?america?', 'a']
2
['?america?', 'r']
1
['war', 'a']
1
['war', 'r']
1
['russia?', 'a']
1
['russia?', 'r']
1
['mak?er', 'a']
1
['mak?er', 'r']
1

answered Apr 7, 2022 at 10:19

Ukulele

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