How to use dynamic variable in array with diff name [closed]

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Here I have code such as following.

$Var =  "Gas";
$Gasname[0] ="abc";
$Gasno[1] = 123;

echo ${$Var."name"[0]};

I have condition on $Var if value is Gas I will user Gase array in else case have to use another array like wise there are dynamic types of array.

Is there a way I can use dynamic array variable name.

This is a very bad idea. Use array with keys: array('gas' => [], 'another_gas' => []') — u_mulder
– u_mulder, Commented Apr 13, 2022 at 14:48

RiggsFolly · Accepted Answer · 2022-04-13 14:47:33Z

1

You were nearly there, the array index is not part of the variable name.

echo ${$Var."name"}[0];

answered Apr 13, 2022 at 14:47

RiggsFolly

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Justinas · Accepted Answer · 2022-04-13 14:47:43Z

1

Move [0] out of ${} part, as it's not part of dynamic name:

$Var =  "Gas";
$Gasname[0] ="abc";
$Gasno[1] = 123;

echo ${$Var."name"}[0];

answered Apr 13, 2022 at 14:47

Justinas

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