how to retrieve the object from array of objects and arrays using javascript

Question

I have array of objects and arrays.

If the array of objects has value property same

and if place includes of arrraylist list return first obj
and if place is equal includes/not includes return first obj

if no above conditions return undefined; using javascript

var list=['SG','TH','MY']


var arrobj1=[
  {id:1, name:'userone',place:'SG', value:100},
  {id:2, name:'usertwo',place:'TH', value:100},
  {id:3, name:'userthree',place:'IL',value:200},
]
Expected Output
{id:1, name:'userone',place:'SG', value:100}

****
var arrobj2=[
  {id:1, name:'userone',place:'IN', value: 200},
  {id:2, name:'usertwo',place:'SL',value: 100},
  {id:3, name:'userthree',place:'SL', value: 100},
]
Expected Output
{id:2, name:'usertwo',place:'SL',value: 100}
****
var arrobj3=[
  {id:1, name:'userone',place:'SL', value:10},
  {id:2, name:'usertwo',place:'IN', value:20},
  {id:3, name:'userthree',place:'KL', value:30},
]
Expected Output
undefined

Tried

var result= arrobj.find(e=>{
  if((e.value === e.value) && (list.includes(e.place)){
   return e
  }
})

What do you mean by if the array of objects has value property same? Please clarify your conditions and perhaps show us how you're trying to meet them in your code. — PeterKA
– PeterKA, Commented Apr 25, 2022 at 15:08
Do you mean: From the array elements with duplicate values, find the first whose place value is in the list, or (failing that) the first whose place is also duplicated in the duplicate values list? This is another example where most of the analytical work must take place in the problem statement. For example, stackoverflow.com/questions/71900081/… — danh
– danh, Commented Apr 25, 2022 at 15:26
@code123 ... isn't this question just another variation of ... "How to get array of objects by arrays in javascript" ... where until now the OP didn't respond to an approach which enables the solution of the OP's 3 different scenarios (requirements)? — Peter Seliger
– Peter Seliger, Commented Apr 27, 2022 at 8:45

Eric Phillips · Accepted Answer · 2022-04-25 15:14:17Z

I've added inline comments to correspond to the requirements. I wasn't sure exactly what you meant in some cases, so I can adjust the answer if you clarify the question

var list = ['SG', 'TH', 'MY']


var arrobj1 = [{
    id: 1,
    name: 'userone',
    place: 'SG',
    value: 100
  },
  {
    id: 2,
    name: 'usertwo',
    place: 'TH',
    value: 100
  },
  {
    id: 3,
    name: 'userthree',
    place: 'IL',
    value: 200
  },
]
//Expected Output
//{id:1, name:'userone',place:'SG', value:100}

//****
var arrobj2 = [{
    id: 1,
    name: 'userone',
    place: 'IN',
    value: 200
  },
  {
    id: 2,
    name: 'usertwo',
    place: 'SL',
    value: 100
  },
  {
    id: 3,
    name: 'userthree',
    place: 'SL',
    value: 100
  },
]
//Expected Output
//{id:2, name:'usertwo',place:'SL',value: 100}
//****
var arrobj3 = [{
    id: 1,
    name: 'userone',
    place: 'SL',
    value: 10
  },
  {
    id: 2,
    name: 'usertwo',
    place: 'IN',
    value: 20
  },
  {
    id: 3,
    name: 'userthree',
    place: 'KL',
    value: 30
  },
]
//Expected Output
//undefined

function getMatch(places, arrObj) {
  // .find will return the first item that matches the condition provided
  return arrObj.find(
    l => list.includes(l.place) // either the place of this item must exist in the list
|| arrObj.filter(arr => arr.value === l.value).length > 1) // or the value of this item must appear more than once in the list
}


console.log(getMatch(list, arrobj1));
console.log(getMatch(list, arrobj2));
console.log(getMatch(list, arrobj3));

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