Python pass filepath to another function

Question

I can't seem to figure out how to pass user_filepath global onto my second function. What can I change to do this? I'm using these two functions in a GUI. I try passing it to split_lines() but that isn't working saying user_filepath is not defined. Could I have some insight onto how to correct this? I'm new with tkinter and handling filepaths.

class Sequence_Class:
"This holds the functions for the button sequence."
global user_filepath

def open_file(): # Defines the function that opens the user's file in specific location.
    user_filepath = askopenfilename(filetypes=[("Text Files", "*.txt"), ("All Files", "*.*")])
    if not user_filepath:
        return
    txt_edit.delete("1.0", tk.END)
    with open(user_filepath, mode="r", encoding="utf-8") as input_file:
        text = input_file.read()
        txt_edit.insert(tk.END, text)
    window.title(f"Linestring Compiler V1.0 - {user_filepath}")

# Defines the function that reads, delimits and quantifies the data.
def split_lines(user_filepath, delimiter, remove = '^[0-9.]+$'):
    for line in user_filepath:
        tokens = line.split(delimiter)
        tokens = [re.sub(remove, "", token) for token in tokens]
        clean_list = list(filter(lambda e:e.strip(), tokens))
    txt_edit.delete("1.0", tk.END)
    with open(user_filepath, mode="r", encoding="utf-8") as input_file:
        clean_list = input_file.read()
        txt_edit.insert(tk.END, clean_list)

def save_file(): # Defines the function that saves the open file to a new location.
    filepath = asksaveasfilename(defaultextension=".txt", filetypes=[("Text Files", "*.txt"), ("All Files", "*.*")],)
    if not filepath:
        return
    with open(filepath, mode="w", encoding="utf-8") as output_file:
        text = txt_edit.get("1.0", tk.END)
        output_file.write(text)
...

btn_compile = tk.Button(frm_buttons, text="Compile Lines", command=Sequence_Class.split_lines(user_filepath, "/"))

rangeseeker · Accepted Answer · 2022-05-10 18:40:03Z

1

Just define filepath at the global level.

filepath = askopenfilename(filetypes=[("Text Files", "*.txt"), ("All Files", "*.*")])

def open_file():
    file_path = filepath
    if not filepath:
        return
    txt_edit.delete("1.0", tk.END)
    with open(filepath, mode="r", encoding="utf-8") as input_file:
        text = input_file.read()
        txt_edit.insert(tk.END, text)
    window.title(f"Linestring Compiler V1.0 - {filepath}")

lines = filepath
def split_lines(lines, delimiter, remove = '^[0-9.]+$'):
    for line in lines:
        tokens = line.split(delimiter)
        tokens = [re.sub(remove, "", token) for token in tokens]
        clean_list = list(filter(lambda e:e.strip(), tokens))
        cleaned_data.append(clean_list)
    txt_edit.delete("1.0", tk.END)
    with open(input_file, mode="r", encoding="utf-8") as input_file:
        text = input_file.read()
        txt_edit.insert(tk.END, text)

It looks like there are some redundant variables, like file_path and lines. You might want to open the file in the global scope and manipulate it in your functions instead of opening it in both functions.

edited May 10, 2022 at 18:40

answered May 10, 2022 at 17:50

rangeseeker

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4 Comments

Chaotic.Python Over a year ago

Thank you, I tried including the global call for filepath, then use that in my other function split_lines() but i'm getting an error that filepath is not defined? Do I need to call lines = filepath in order to use my second function?

rangeseeker Over a year ago

My apologies, this solution is wrong. Correcting now.

Chaotic.Python Over a year ago

Hi @rangeseeker, will this work the same if I use the global within a class?

rangeseeker Over a year ago

A class will be able to access a global variable.

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