I have 2 array and i will filtered but key duplicate.
const arr1 = [1, 2, 3, 3, 3, 4];
const arr2 = [1, 3];
function filteredArray(arr1, arr2) {...}
const newArr = filteredArray(arr1, arr2);
console.log(newArr);
// result: [2, 3, 3, 4];
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2 Answers
You can check the below implementation. We should not modify the original data as well, that's why I've cloned your array for the array modification instead of changing items on the original one.
const arr1 = [1, 2, 3, 3, 3, 4];
const arr2 = [1, 3];
function filteredArray(arr1, arr2) {
const newArr1 = [...arr1] //clone the array to keep the original array data
const set2 = new Set(arr2)
for(let i = 0; i < newArr1.length; i++) {
if(set2.has(newArr1[i])) {
set2.delete(newArr1[i])
newArr1.splice(i,1)
}
}
return newArr1
}
const newArr = filteredArray(arr1, arr2);
console.log(newArr);2 Comments
joy sahimar
Thanks for answer. but sorry, result not expected.
Nick Vu
Ah I misunderstood your question, let me try to arrange my answer again @joysahimar
Use set and filter
function filteredArray(arr1, arr2) {
const set = new Set(arr2);
return arr1.filter(item => !set.delete(item));
}
const arr1 = [1, 2, 3, 3, 3, 4];
const arr2 = [1, 3];
console.log(filteredArray(arr1, arr2));
answered Jun 29, 2022 at 4:46
Siva Kondapi Venkata
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