How to export class's of css and put into array with php?

Question

hello guyes I have CSS code and I'm trying to find a way to get only the CSS Class's name Only and clear coma and open&close tag and value and put it into an array in PHP

Example:

.dungarees {
  content: "\ef04";
}
.jacket {
  content: "\ef05";
}
.jumpsuit {
  content: "\ef06";
}
.shirt {
  content: "\ef07";
}

and I want to do a a function with PHP to convert it into an array like this

$my_array('dungarees','jacket','jumpsuit','shirt');

is there any function with php or even jquery to deal with this? thanks

Welcome to Stack Overflow. Do you mean to do this in PHP or in JavaScript? Are you looking to read the Class names from the CSS file itself? — Twisty
– Twisty, Commented Jul 1, 2022 at 17:58
Take a look at this suggestion: stackoverflow.com/a/3618436/1248114 — arkascha
– arkascha, Commented Jul 1, 2022 at 18:07
Does this answer your question? php to get all class names in css file — imvain2
– imvain2, Commented Jul 1, 2022 at 18:07
Also do you want just stand alone classes? For example, if you had div.jacket or .jacket.small Should those be included or ignored. Please provide more details about what you are trying to accomplish and what you have tried. — Twisty
– Twisty, Commented Jul 1, 2022 at 18:26

Markus Zeller · Accepted Answer · 2022-07-01 18:23:43Z

1

You can create such an array with a simple Regex.

$cssText = <<<'_CSS'
.dungarees {
  content: "\ef04";
}
.jacket {
  content: "\ef05";
}
.jumpsuit {
  content: "\ef06";
}
.shirt {
  content: "\ef07";
}
_CSS;

$matches = [];
preg_match_all('/\.([\w\-]+)/', $cssText, $matches);
$myArray = $matches[1];

print_r($myArray);

And will result in

Array
(
    [0] => dungarees
    [1] => jacket
    [2] => jumpsuit
    [3] => shirt
)

edited Jul 1, 2022 at 18:23

answered Jul 1, 2022 at 18:16

Markus Zeller

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Comments

IT goldman · Accepted Answer · 2022-07-01 18:05:37Z

0

Scan the string line by line, expecting it to begin with . and end with {

<?php
$result = [];
$content_of_css = '
.dungarees {
    content: "\ef04";
  }
  .jacket {
    content: "\ef05";
  }
  .jumpsuit {
    content: "\ef06";
  }
  .shirt {
    content: "\ef07";
  }

';

// or $content_of_css = file_get_contents("path_to_css");

$arr = explode("\n", $content_of_css);
foreach ($arr as $line) {
    $line = trim($line);
    if (strrpos($line, ".") === 0) {
        $result[] = trim(substr($line, 1, strlen($line) - 2));
    }
}

answered Jul 1, 2022 at 18:05

IT goldman

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