Python: loop and edit string character

Question

I'm new to python and coding in general. Here is a problem from my homework, as well as my current code. I know that I only have one of the parts, but I wanted to figure this one out before moving on to the rest. With my loop, I can find and identify the letter i, but I can't figure out how to change the i's to 1's.

Problem:

Many user-created passwords are simple and easy to guess. Write a program that takes a simple password and makes it stronger by replacing characters using the key below, and by appending "!" to the end of the input string.
i becomes 1
a becomes @
m becomes M
B becomes 8
s becomes $
Ex: If the input is:
mypassword
the output is:
Myp@$$word!
Hint: Python strings are immutable, but support string concatenation. Store and build the stronger password in the given password variable.

Code:

word = input()
password = ()


for letter in word:
    if letter == 'i':
        password = password+'1'
    else: password = password+letter

print(password)

input: igigigig
output: igigigig

Your code has an error, the password should be initialized with an empty string "". Also this should do — Geeky Quentin
– Geeky Quentin, Commented Jul 6, 2022 at 1:44

flakes · Accepted Answer · 2022-07-06 01:55:28Z

3

First off, you're initializing your password to an incorrect variable choice. password = () sets password to a tuple. Attempting to add characters to a tuple variable will lead to an exception:

>>> password = ()
>>> password = password + '1'
Traceback (most recent call last):
  File "<input>", line 1, in <module>
TypeError: can only concatenate tuple (not "str") to tuple

Next, you have a mapping of characters provided in the question. You can start by creating a dictionary to represent this mapping.

mapping = {
    'i': '1',
    'a': '@',
    'm': 'M',
    'B': '8',
    's': '$',
}

When looping against letters you can use the mapping to determine if a replacement should be made:

for letter in word:
    if letter in mapping:
        password = password + mapping.get(letter)
    else:
        password = password + letter

You also forgot to add the ! to the end.

Final result:

mapping = {
    'i': '1',
    'a': '@',
    'm': 'M',
    'B': '8',
    's': '$',
}

word = "mypassword"
password = ""

for letter in word:
    if letter in mapping:
        password = password + mapping[letter]
    else:
        password = password + letter
password += "!"

print(password)

Simplifying this further:

for letter in word:
    password += mapping.get(letter, letter)
password += "!"

Even further with a comprehension!:

password = ''.join(mapping.get(l, l) for l in word) + "!"

edited Jul 6, 2022 at 1:55

answered Jul 6, 2022 at 1:45

flakes

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1 Comment

Matt P Over a year ago

Thanks a ton! we haven't learned mappings yet, but i'll have to take a look at them. they seem very useful!

Sunny · Accepted Answer · 2022-07-06 01:56:51Z

0

you can flow the step below

1.Change str(word) to list off str(letter)
2.Use loop check and change str(letter) in list one by one
3.Merge list off str(letter) to str(word)

Code :

word = list(word)

for position in range(len(word)):
    letter = word[position]
    if letter == 'i':
        word[position] = '1'

''.join(word)

answered Jul 6, 2022 at 1:56

Sunny

111 bronze badge

Comments

Matt P · Accepted Answer · 2022-07-06 03:52:03Z

0

with the help of some of these comments and re-reading the instructions, I was able to find the right answer that the book was looking for.

word = input()
password=''


for letter in word:
    if letter == 'i':
        str1 = '1'
        password = password+str1
    else: password = password+letter

print(password)

answered Jul 6, 2022 at 3:52

Matt P

334 bronze badges

Comments

SergFSM · Accepted Answer · 2022-07-06 07:27:36Z

0

no need to loop, just do translate:

pswd = 'mypassword'
pswd = pswd.translate(str.maketrans('iamBs','1@M8$'))+'!'

print(pswd) # Myp@$$word!

answered Jul 6, 2022 at 7:27

SergFSM

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