I wrote a program that examines whether a number in a sequence is repeated 2 times (so many times it should be repeated) if it is repeated 2 times "YES", if not "NO". I think this can be written in a simpler and better way, so I'm interested in the suggestions and corrections of someone more experienced than me.
The program should print YES if each member of array is repeated exactly once, and otherwise it should print NO:
Enter the number of array: 8
Enter the sequence: 1 2 2 1 3 3 4 4
YES
Enter the number of string members: 7
Enter the string: 1 2 1 2 1 3 4
NO
Here is my code:
#include <stdio.h>
#define arr 100
int main() {
int n, i, p = 1, j, a;
double array[arr];
int num[100];
do {
printf("Enter the number of array: ");
scanf("%d", &n);
} while (n < 1 || n > 100);
printf("Enter array: ");
for (i = 0; i < n; i++) {
scanf("%lf", &array[i]);
num[i] = -1;
}
for (i = 0; i < n; i++) {
a = 1;
for (j = i + 1; j < n; j++) {
if (array[i] == array[j]) {
a++;
num[j] = 0;
}
}
if (num[i] != 0)
num[i] = a;
}
for (i = 0; i < n; i++) {
if (num[i] == 0)
continue;
if (num[i] != 2) {
p = 0;
break;
}
}
if (p == 1)
printf("YES");
else
printf("NO");
return 0;
}