Alphabetically sorting an array within an array in Ruby?

Question

Method input: ["eat","tea","tan","ate","nat","bat"]

I have grouped each of the anagrams into their own array within an array through this method and then sorted the array by group size:

def group_anagrams(a)
    a.group_by { |stringElement| stringElement.chars.sort }.values.sort_by(&:size)
end

I am struggling to figure out how to alphabetically sort the resulting arrays within the array here because as you can see nat should come before tan in the middle element of the array:

[["bat"], ["tan", "nat"], ["eat", "tea", "ate"]]

Updating with final solution:

def group_anagrams(a)
    a.group_by { |stringElement| stringElement.chars.sort }.values.map(&:sort).sort_by(&:size)
end

Chris · Accepted Answer · 2022-09-01 22:47:11Z

2

You need to map this array and sort (map(&:sort))

def group_anagrams(ary)
  ary.group_by { |s| s.chars.sort }.values.map(&:sort)
end

ary = ["eat", "tea", "tan", "ate", "nat", "bat"]
group_anagrams(ary)
# => [["ate", "eat", "tea"], ["nat", "tan"], ["bat"]]

edited Sep 1, 2022 at 22:47

Chris

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answered Sep 1, 2022 at 21:01

mechnicov

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1 Comment

Chris Over a year ago

Please note that this works equally well whether it's ary.group_by { |se| se.chars.sort }.values.map(&:sort).sort_by(&:size) or ary.group_by { |se| se.chars.sort }.values.sort_by(&:size).map(&:sort) (shortened name for brevity's sake)

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