Replace value of variable directly inside f-string

Question

I'm trying to replace a value inside a variable that I use within an f-string. In this case it is a single quote. For example:

var1 = "foo"
var2 = "bar '"

print(f"{var1}-{var2}")

Now, I want to get rid of the single quote within var2, but do it directly in the print statement. I've tried:

print(f"{var1}-{var2.replace("'","")}")

which gives me: EOL while scanning string literal.

I do not want to impose a third variable, so no var3 = var2.replace(",","") etc...

I would rather not use a regex, but if there is no other way, please tell me how to do it.

What is the best way to solve this?

wim · Accepted Answer · 2022-09-12 17:36:49Z

3

When the contents contains both ' and ", you can use a triple quoted string:

>>> print(f'''{var1}-{var2.replace("'","")}''')
foo-bar

answered Sep 12, 2022 at 17:36

wim

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5 Comments

JVGBI Over a year ago

oh wow, that's both the easiest and fastest solution I've ever gotten. Thank you so much!

Matthias Over a year ago

Bonus: Triple quoted strings can span multiple lines and keep the newline character in the string.

Mad Physicist Over a year ago

You can nest one layer further, since you have access to both single and double triple quoted strings. That being said, this is probably a moment when you should step back and ask yourself if you ever plan on being able to read this code in the future.

JVGBI Over a year ago

@Matthias that I knew and already use, but just couldn't wrap my head around it why I need 3 quotes for such a replace (and still can't but hey it works :))

Mad Physicist Over a year ago

@JVGBI. Because you can't escape things in an f-string

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