const names = 'const names = ["jhon", "anna", "kelvin"]'
how to get the names array so i can loop through it
for example names.forEach(name => console.log(name))
// expected results jhon, anna, kelvin
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Why you take the const in the let? This approach is not right. You can take the array in let names.Asif Jalil– Asif Jalil2022-09-17 06:22:10 +00:00Commented Sep 17, 2022 at 6:22
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because i take the code from the user input (in my real project)Esa Kurniawan– Esa Kurniawan2022-09-17 06:37:31 +00:00Commented Sep 17, 2022 at 6:37
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1Whatever you do, avoid the eval and use something like stackoverflow.com/a/73752586/1277159WSD– WSD2022-09-17 06:52:18 +00:00Commented Sep 17, 2022 at 6:52
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i take the code from the user input (in my real project). That gives me shivers...Rodrigo Rodrigues– Rodrigo Rodrigues2022-09-17 09:12:02 +00:00Commented Sep 17, 2022 at 9:12
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4 Answers
You could use match() here to isolate the array, followed by a split() to obtain a list of names.
var names = 'const names = ["jhon", "anna", "kelvin"]';
var vals = names.match(/\["(.*?)"\]/)[1]
.split(/",\s*"/)
.forEach(name => console.log(name));
Comments
You can try this one:
let testCase1 = 'const names = ["jhon", "anna", "kelvin"]';
let testCase2 = 'var names = ["cane", "anna", "abel", 1, {}, []]';
let testCase3 = 'var names = ["cane" "anna", "abel", 1, {}, []]';
function getArrayLikeInsideText(text) {
const regex = new RegExp(/\[.*\]/, 'g');
const temp = text.match(regex);
let arr;
try {
arr = JSON.parse(temp);
} catch {
return undefined;
}
const gotAnArray = Array.isArray(arr);
return gotAnArray ? arr : undefined;
}
console.log(getArrayLikeInsideText(testCase1)); // ["jhon", "anna", "kelvin"]
console.log(getArrayLikeInsideText(testCase2)); // ["cane", "anna", "abel", 1, {}, []]
console.log(getArrayLikeInsideText(testCase3)); // undefined
2 Comments
Esa Kurniawan
that works perfectly for my use cases, but it's using the eval function can you refactor it to not using the eval function?
Ghost
Ok, I rewrite it using JSON.parse instead of eval. Still work fine.
eval('const names = ["jhon", "anna", "kelvin"]');
for(let name : names)
console.log(name);
1 Comment
Saravanan
There are downsides of using
eval which you need to highlight to the user and this a code only answerYou can simply achieve this by using a RegEx with the help of String.match() method.
Live Demo :
const names = 'const names = ["jhon", "anna", "kelvin"]';
const a = names.match(/\[.*\]/g)[0];
JSON.parse(a).forEach(name => console.log(name));\[.*\] - Including open/close brackets along with the content.
