Variable not populating in a bash script

Question

I'm having a duh moment. I'm not getting this variable populated.

for i in ~/Ws/*.png; 
do 
  echo $i; 
  FNAME=cmd basename $i;
  echo $FNAME;
done;

I am getting the following output for example

home/Ws/BrainLearning.png
BrainLearning.png

But the last line is blank and I do not understand why. Basically $FNAME is not populated with the information I was expecting.

you imply that you don't have something that you expect, but there is no description of what you expect. What do you want to store in FNAME ? — LeGEC
– LeGEC, Commented Sep 28, 2022 at 11:08

LeGEC · Accepted Answer · 2022-09-28 11:10:08Z

1

If your intention is to have FNAME filled with the basename of $i :

FNAME=$(basename $i)
echo "FNAME: $FNAME"

answered Sep 28, 2022 at 11:10

LeGEC

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Comments

Antonio Petricca · Accepted Answer · 2022-09-28 10:16:21Z

0

Change

FNAME=cmd basename $i;

into

FNAME="cmd $(basename $i)";

answered Sep 28, 2022 at 10:16

Antonio Petricca

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anubhava · Accepted Answer · 2022-09-28 10:44:12Z

0

Your shown code has syntax errors and I suggest running your script on shellcheck.net

However what you're attempting to do can be done using this find command as well without any loop:

find ~/Ws -name '*.png' -execdir echo {} +

answered Sep 28, 2022 at 10:44

anubhava

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