pop/shift a ruby array multiple times

Question

My code currently looks like this

numbers = [1, 2, 3, 4, 5]

def pop_three
  pop = []
  3.times { pop << numbers.pop }
  return pop
end

Is there any way to do what's inside the pop_three method in one line?

I basically want to do something like numbers.slice(0, 3) but deleting the array items that are in the slice.

Uhm...hrmmm, I think I just realized I can try slice!

mb14 · Accepted Answer · 2011-09-12 16:02:02Z

8

Yes

numbers.pop(3)

Or

numbers.shift(3)

If you want this other side.

answered Sep 12, 2011 at 16:02

mb14

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5 Comments

Interesting, wonder when they added that. The docs I have don't mention any parameters.

you could have added the shift one to pass the limit ;-)

@brand I didn't read the doc. Just tried. Sometimes Ruby act as expected ;-)

Array#pop|shift accepts parameters since Ruby 1.8.7. See for instance RubySpec ( github.com/rubyspec/rubyspec/blob/master/core/array/… ).

Here's the updated link since these specs are now under the github/ruby repo (github.com/ruby/ruby/blob/master/spec/ruby/core/array/…) @Marc-AndréLafortune

cpjolicoeur · Accepted Answer · 2011-09-12 16:01:28Z

0

what about numbers.slice(x.size-3,3).reverse

answered Sep 12, 2011 at 16:01

cpjolicoeur

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