Javascript function return as object property

Question

I'm trying to return the value of a function as an object property (as opposed to the function itself). This is my code right now, but it breaks when I try to access option_list[0][0].label or .value within my jQuery plugin. Thoughts?

$('#new').create({
    option_list:function(){return [
        [
            {label:'option1', value:'1'},
            {label:'option2', value:'2'},
            {label:'option3', value:'3'}
        ]
    ];}
});

broofa · Accepted Answer · 2011-09-16 22:21:03Z

8

You need to actually invoke the function, like so ...

$('#new').create({
    option_list:(function(){return [
        [
            {label:'option1', value:'1'},
            {label:'option2', value:'2'},
            {label:'option3', value:'3'}
        ]
    ];}())
});

answered Sep 16, 2011 at 22:21

broofa

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Comments

notion · Accepted Answer · 2011-09-16 22:21:36Z

-1

Maybe I get you wrong but why do you want to have such a multidimensional array?

Let the function give you an object with an encapsulated array:

$('#new').create({
    option_list:function(){ return {
        [
            {label:'option1', value:'1'},
            {label:'option2', value:'2'},
            {label:'option3', value:'3'}
        ]
    };}
});

answered Sep 16, 2011 at 22:21

notion

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1 Comment

Tim Over a year ago

without full context, it seems superfluous, but it's part of a bigger form-generation schema. is there a reason returning and object vs. an array would be better?

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