How to replace string in a array using sed in shell script

Question

I have a array declared in a file and i want to replace/update array with latest values. below is the array saved in a file.

declare -A IMAGES_OVERRIDE
IMAGES_OVERRIDE=(
[service1]='gcr.io/test-project/image1:latest'
[service2]='gcr.io/test-project/image2:9.5.16'
[service3]='gcr.io/test-project/data/image3:latest'
)

Now I want to update service2 with latest image gcr.io/test-project/image2:10.0.1 and save into file.

I tried like below

sed -i 's/[service2]=.*/[service2]='gcr.io/test-project/image2:10.0.1'/' ./override

but I am getting below error.

sed: -e expression #1, char 35: unknown option to `s'

Same command is working me for other script but that is not array.

What research did you do on your own? And what exact errors do you have hard time with? (please add the info to your question) Note that we are not here to solve people's issues upon request. How to ask a Question How to create a Minimal, Reproducible Question — Ron
– Ron, Commented Dec 12, 2022 at 9:27

Arnaud Valmary · Accepted Answer · 2022-12-12 10:05:25Z

2

Simply:

> sed -i "s#\[service2\]=.*#[service2]='gcr.io/test-project/image2:10.0.1'#" ./override

Notes:

Use " instead of ' around sed expression (your sed script contains ');
Use # instead of / to limit each part of sed replace expression (your new token contains /);
Use \ before each [ and ] in RE expression ([ and ] are special RE characters);

edited Dec 12, 2022 at 10:05

answered Dec 12, 2022 at 9:48

Arnaud Valmary

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