Fill an array with random numbers android/ java

Question

I'm having trouble doing the following and have no idea how to do it: I would like to fill an array generated with random numbers (1-40) and also make it so that the number doesn't repeat. Also, is there a way to make the array go to the next value on its own using. So let say I have test [1] = "3" and then test [2] = "6". Is there anyway to make it go to the next value instead of calling test [2]?

Thanks a lot

possible duplicate of android: generate random number without repetition — Matt Ball
– Matt Ball, Commented Oct 1, 2011 at 18:00

Eng.Fouad · Accepted Answer · 2011-10-01 18:08:57Z

8

List<Integer> list = new ArrayList<Integer>();
for(int i = 0; i < 40;)
{
    int rand = ((int)(Math.random() * 40)) + 1;
    if(!list.contains(rand))
    {
        list.add(rand);
        i++;
    }
}

or:

List<Integer> list = new ArrayList<Integer>();
for(int i = 0; i < 40; i++) list.add(i);
Collections.shuffle(list);

edited Oct 1, 2011 at 18:08

answered Oct 1, 2011 at 18:03

Eng.Fouad

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