Given a string that is a sequence of several values separated by a commma:
mStr = 'A,B,C,D,E'
How do I convert the string to a list?
mList = ['A', 'B', 'C', 'D', 'E']
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Related Convert string representation of list to list in PythonBhargav Rao– Bhargav Rao2016-06-22 10:29:50 +00:00Commented Jun 22, 2016 at 10:29
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7 Answers
You can use the str.split method.
>>> my_string = 'A,B,C,D,E'
>>> my_list = my_string.split(",")
>>> print my_list
['A', 'B', 'C', 'D', 'E']
If you want to convert it to a tuple, just
>>> print tuple(my_list)
('A', 'B', 'C', 'D', 'E')
If you are looking to append to a list, try this:
>>> my_list.append('F')
>>> print my_list
['A', 'B', 'C', 'D', 'E', 'F']
1 Comment
johndodo
Careful though, splitting an empty string does not return what one might have expected:
"".split(",") returns [""] (a list with one element, which is empty string).In the case of integers that are included at the string, if you want to avoid casting them to int individually you can do:
mList = [int(e) if e.isdigit() else e for e in mStr.split(',')]
It is called list comprehension, and it is based on set builder notation.
ex:
>>> mStr = "1,A,B,3,4"
>>> mList = [int(e) if e.isdigit() else e for e in mStr.split(',')]
>>> mList
>>> [1,'A','B',3,4]
Comments
Consider the following in order to handle the case of an empty string:
>>> my_string = 'A,B,C,D,E'
>>> my_string.split(",") if my_string else []
['A', 'B', 'C', 'D', 'E']
>>> my_string = ""
>>> my_string.split(",") if my_string else []
[]
Comments
You can split that string on , and directly get a list:
mStr = 'A,B,C,D,E'
list1 = mStr.split(',')
print(list1)
Output:
['A', 'B', 'C', 'D', 'E']
You can also convert it to an n-tuple:
print(tuple(list1))
Output:
('A', 'B', 'C', 'D', 'E')
2 Comments
Jaimil Patel
Hope It will solve issue but please add explanation of your code with it so user will get perfect understanding which he/she really wants.
stackprotector
Looks like a duplicate of the already accepted answer (9 years ago).
>>> some_string='A,B,C,D,E'
>>> new_tuple= tuple(some_string.split(','))
>>> new_tuple
('A', 'B', 'C', 'D', 'E')
answered Oct 21, 2011 at 1:39
Raymond Hettinger
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Comments
You can use this function to convert comma-delimited single character strings to list-
def stringtolist(x):
mylist=[]
for i in range(0,len(x),2):
mylist.append(x[i])
return mylist
Comments
#splits string according to delimeters
'''
Let's make a function that can split a string
into list according the given delimeters.
example data: cat;dog:greff,snake/
example delimeters: ,;- /|:
'''
def string_to_splitted_array(data,delimeters):
#result list
res = []
# we will add chars into sub_str until
# reach a delimeter
sub_str = ''
for c in data: #iterate over data char by char
# if we reached a delimeter, we store the result
if c in delimeters:
# avoid empty strings
if len(sub_str)>0:
# looks like a valid string.
res.append(sub_str)
# reset sub_str to start over
sub_str = ''
else:
# c is not a deilmeter. then it is
# part of the string.
sub_str += c
# there may not be delimeter at end of data.
# if sub_str is not empty, we should att it to list.
if len(sub_str)>0:
res.append(sub_str)
# result is in res
return res
# test the function.
delimeters = ',;- /|:'
# read the csv data from console.
csv_string = input('csv string:')
#lets check if working.
splitted_array = string_to_splitted_array(csv_string,delimeters)
print(splitted_array)
Comments
