I have a python script running in background, and I want to log all the exception and output to a log file.
I know to use logging module and try.. catch.. to log exception, but what if I missed some, is there any way to log these exceptions too?
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possible duplicate of Python: Temporarily Redirect stdout/stderrg.d.d.c– g.d.d.c2011-10-27 03:42:53 +00:00Commented Oct 27, 2011 at 3:42
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2 Answers
The usual technique is to use a try/except Exception at the highest level call (the main function). This pretty much assures that you will not have "missed some". Exception matches non-exiting exceptions, so it is casting a broad net.
answered Oct 27, 2011 at 3:46
Raymond Hettinger
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You can reassign sys.stdout and sys.stderr to file handles. They'll be available after your python exits if an uncaught exception is encountered. Something like this:
import sys
sys.stdout = open('myOut.txt', 'w')
sys.stderr = open('myErr.txt', 'w')
2 Comments
lxyu
this will not add time on an exception quit, is it? I'm wondering if any way would work as the logging module's behavior.
g.d.d.c
@lxyu - I ... am not sure what you are asking. This will redirect all of stdout or stderr to files, useful for when you'll be running a script in the background or in some way unattended and want a record of what it outputs. The
logging module supports the write(str) method, which means you could assign an instance of a log to either or both of these.