Using if else inside array-php

Question

being new to php i am not ble to figure out how to use if else inside php array. i tried to do something like this

function column_title($item){
        $status=false;
        if($item->uTestimonials_approval =='0')
           $status=false;
         else
          $status=true;

        //Build row actions
        $actions = array(
             $status ? 'unapprove'      => sprintf('<a href="?page=%s&action=%s&id=%s">Unapprove</a>',$_REQUEST['page'],'unapprove',$item-> uTestimonials_id),:
            'approve1'      => sprintf('<a href="?page=%s&action=%s&id=%s">Approve</a>',$_REQUEST['page'],'approve',$item-> uTestimonials_id),

            'delete'    => sprintf('<a href="?page=%s&action=%s&id=%s">Delete</a>',$_REQUEST['page'],'delete',$item-> uTestimonials_id),
        );

        //Return the title contents
        return sprintf('%1$s <span style="color:silver">(id:%2$s)</span>%3$s',
            /*$1%s*/ $item-> uTestimonials_message,
            /*$2%s*/ $item-> uTestimonials_id,
            /*$3%s*/ $this->row_actions($actions)
        );
    }

but i am getting following parsing exception

Parse error: syntax error, unexpected T_DOUBLE_ARROW

can any one help me to find what exactly i am doing wrong thanks in advance

I am perfectly fine for negative voting but its always better to specify why some one did that so that person can improve him/herself

@Jeune i am working on some wordpress functionality and based on the approval status i need to show certain text to use so i am using this. — Umesh Awasthi
– Umesh Awasthi, Commented Nov 7, 2011 at 16:21
To let you know, whole your code, with all this sprintf and ternary being extremely unreadable — Your Common Sense
– Your Common Sense, Commented Nov 7, 2011 at 16:22

Naftali · Accepted Answer · 2011-11-07 16:17:30Z

5

You cannot do this for a key value:

 $status ? 'unapprove'

Try something like this instead:

    //Build row actions
    $ap = 'approve';
    $key = 'approve1';
    if($status){             
       $ap = 'unapprove';
       $key = 'unapprove';
    }
    $actions = array(
        $key => sprintf('<a href="?page=%s&action=%s&id=%s">'.$ap.'</a>',$_REQUEST['page'],$ap,$item-> uTestimonials_id),:
        'delete' => sprintf('<a href="?page=%s&action=%s&id=%s">Delete</a>',$_REQUEST['page'],'delete',$item-> uTestimonials_id),
    );

answered Nov 7, 2011 at 16:17

Naftali

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6 Comments

Umesh Awasthi Over a year ago

any idea how i can achieve the desired thing as i have to use key and a value against it

Your Common Sense Over a year ago

@user what about just a regular if setting a variable before array definition code, eh?

Naftali Over a year ago

@Col.Shrapnel I added that ^_^

aziz punjani Over a year ago

No need to do that, you can use shorthand notation for an array key. He just didn't specify the else portion of it that's why it was throwing an error.

Naftali Over a year ago

@Interstellar_Coder look at the OP's code, the else was specified, but in the wrong place.

|

kapa · Accepted Answer · 2011-11-07 16:19:38Z

2

You cannot do that inside the array definition.

Instead, you could add these to the array after the definition like this:

$actions = array(
    'delete'    => sprintf('<a href="?page=%s&action=%s&id=%s">Delete</a>',$_REQUEST['page'],'delete',$item-> uTestimonials_id),
);

if ($status) {
    $actions['unapprove'] = sprintf('<a href="?page=%s&action=%s&id=%s">Unapprove</a>',$_REQUEST['page'],'unapprove',$item-> uTestimonials_id);
}
else {
    $actions['approve'] = sprintf('<a href="?page=%s&action=%s&id=%s">Approve</a>',$_REQUEST['page'],'approve',$item-> uTestimonials_id);
}

answered Nov 7, 2011 at 16:19

kapa

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