Basically, the user submits a String which the Iterator searches an ArrayList for. When found the Iterator will delete the object containing the String.
Because each of these objects contain two Strings, I am finding trouble writing these lines as one.
Friend current = it.next();
String currently = current.getFriendCaption();
Thanks for any help!
You don't need them on one line, just use remove to remove an item when it matches:
Iterator<Friend> it = list.iterator();
while (it.hasNext()) {
if (it.next().getFriendCaption().equals(targetCaption)) {
it.remove();
// If you know it's unique, you could `break;` here
}
}
Full demo:
import java.util.*;
public class ListExample {
public static final void main(String[] args) {
List<Friend> list = new ArrayList<Friend>(5);
String targetCaption = "match";
list.add(new Friend("match"));
list.add(new Friend("non-match"));
list.add(new Friend("match"));
list.add(new Friend("non-match"));
list.add(new Friend("match"));
System.out.println("Before:");
for (Friend f : list) {
System.out.println(f.getFriendCaption());
}
Iterator<Friend> it = list.iterator();
while (it.hasNext()) {
if (it.next().getFriendCaption().equals(targetCaption)) {
it.remove();
// If you know it's unique, you could `break;` here
}
}
System.out.println();
System.out.println("After:");
for (Friend f : list) {
System.out.println(f.getFriendCaption());
}
System.exit(0);
}
private static class Friend {
private String friendCaption;
public Friend(String fc) {
this.friendCaption = fc;
}
public String getFriendCaption() {
return this.friendCaption;
}
}
}
Output:
$ java ListExample Before: match non-match match non-match match After: non-match non-match
if(it.next().contains(text)) { It doesn't work? I need to only search a certain part (String caption) of each object in the ArrayList.
Iterator correctly, and that you're treating what it returns correctly. For instance, your example there if (it.next().contains(text)) { is acting like the Iterator is iterating over strings, but your question makes it look like the ArrayList contains Friend objects, not strings. The full demo shows how to do it correctly. Key bit is declaring Iterator<Friend> so the Iterator is iterating over Friend instances, so that it.next() will be a Friend, then you can do if (it.next().getFriendCaption().contains(text)) {.