Regex based replace in js

Question

actually I want to replace a string except if it comes in a round bracket.

For example:

JAVA is a nice language. (JAVA) has lots of features. JAVA is portable. (JAVA) even comes in 64 bit.

now if i replace JAVA with C:

then desired output is :

C is a nice language. (JAVA) has lots of features. C is portable. (JAVA) even comes in 64 bit.

even java can come as a sub string like

 XJAVAX is a nice language. (XJAVAX) has lots of features. JAVA is portable. (JAVA) even comes in 64 bit.

now if i replace JAVA by C :

Then expected output :

XCX is a nice language. (XJAVAX) has lots of features. C is portable. (JAVA) even comes in 64 bit.

it's just an example..i din't really mean it..I hope u r confused..I would suggest u 2 leave s/w industry and join some ..... — Neel
– Neel, Commented Nov 23, 2011 at 9:16
I think that those whose upvoted the comment @Mudassir understood the stuff. — Shashank_Itmaster
– Shashank_Itmaster, Commented Nov 23, 2011 at 10:52

T.J. Crowder · Accepted Answer · 2011-11-23 09:16:50Z

3

Since JavaScript doesn't have look-behind, the easiest way is probably an alternation:

str = str.replace(/\(JAVA\)|JAVA/g, function(m) {
    return m === "(JAVA)" ? m : "C";
    // Or
    // return m.length === 6 ? m : "C";
});

Beyond that, you get into trying to simulate look-behind, which is possible in some ways, but messy.

answered Nov 23, 2011 at 9:16

T.J. Crowder

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T.J. Crowder Over a year ago

@Neel: That's probably easily addressed by putting a word boundary marker on either side of the alternation: \b\(JAVA\)|JAVA\b. Running out the door so I couldn't test that. The MDC page on RegExp can be a useful guide. The spec has all the details, but it's not as readable.

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