Issue with adding function in functions.php [Wordpress]

Question

I write function in functions.php like this

function out() {
  $s = 'End of the post, thanks for reading';
  return $s;
}

add_filter('the_content','out');

and I expect this to be fetched at the end of the post, after entry content. But all it does is that post entry ( what the_content outputs) is not shown, and I only get 'End of the post, thanks for reading'.

What am I doing wrong?

Cyclonecode · Accepted Answer · 2019-10-19 07:23:40Z

1

Try this:

function out($content) {
  return $content . ' End of the post, thanks for reading';
}
add_filter( 'the_content', 'out' );

edited Oct 19, 2019 at 7:23

answered Nov 26, 2011 at 15:13

Cyclonecode

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2 Comments

zack Over a year ago

thanks man this works. so I need every time to pass parameter to the function? And than return the same parameter?

Cyclonecode Over a year ago

Check out this page: codex.wordpress.org/Plugin_API/Filter_Reference/the_content

Shakti Singh · Accepted Answer · 2011-11-26 15:14:08Z

1

Can you try this

function out($content) {
  $content .= '<br>End of the post, thanks for reading';
  return $content;
}

add_filter('the_content','out');

answered Nov 26, 2011 at 15:14

Shakti Singh

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