I've a BufferedInputStream from which I want to parse XML with SAXParser but then reuse it again (eg. mark(int) & reset()). However this stream is closed in parse() method. Is it possible to somehow tell SAXParser to leave it open? The last resort is to wrap this stream with un-closeable stream.
Thank you.
How about something like:
class WontCloseBufferedInputStream extends BufferedInputStream {
public void close () {
// Do nothing.
}
public void reallyClose() {
super.close ();
}
}
I use the follwing wrapper for the InputStream to prevent the parser from closing the original stream:
private static class InputStreamWrapper extends InputStream {
private InputStream input;
public InputStreamWrapper(InputStream input) {
this.input = input;
}
@Override
public int read() throws IOException {
return input.read();
}
// Must be overriden for better performance
@Override
public int read(byte[] b, int off, int len) throws IOException {
return input.read(b, off, len);
}
@Override
public void close() {
}
}
The wrapper is used like saxParser.parse(new InputStreamWrapper(input), handler).
Putting the InputStream in an InputSource does not help. This is done internally by the SAX parser.
You can pass InputSource object rather than InputStream object to SAXParser
sample code
SAXParser parser = // saxpaser object
InputSource isource = new InputSource();
InputStream istream = //your inputstream
isource.setByteStream(istream);
parser.parse(isource, handler);
InputSource closed when the parser completes? If so this is unhelpful.