How to get the last array from multiple arrays?

Question

I have an array that has some other arrays inside it:

if I print_r($u) I get:

Array
(
    [0] => Albany
)
Array
(
    [0] => Albany
Array
(
    [0] => Albany
    [41] => Albuquerque
)
Array
(
    [0] => Albany
    [41] => Albuquerque
)
Array
(
    [0] => Albany
    [41] => Albuquerque
    [54] => Atlanta
)
Array
(
    [0] => Albany
    [41] => Albuquerque
    [54] => Atlanta
)
Array
(
    [0] => Albany
    [41] => Albuquerque
    [54] => Atlanta
    [93] => Auckland
    [94] => Augusta
)
Array
(
    [0] => Albany
    [41] => Albuquerque
    [54] => Atlanta
    [93] => Auckland
    [94] => Augusta
)

...

The last array has about 20 elements. I need only that last array. Hope this is not too confusing.

It doesn't look like you have an multi-dimensional array ("array with other arrays inside it"). It looks like you are printing out the array $u while you loop though it and add elements. — NullUserException
– NullUserException, Commented Dec 1, 2011 at 18:17

user142162 · Accepted Answer · 2011-12-01 18:17:08Z

5

You can use the end() function:

$last_array = end($u);

Keep in mind that calling end() will change the internal array pointer. If you don't want that to happen, you could do:

$last_array = $u[count($u) - 1]; // make sure count($u) > 0

answered Dec 1, 2011 at 18:17

user142162

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Comments

Jon · Accepted Answer · 2011-12-01 18:17:12Z

0

If you want to just get the last item out of an array $u, you can do it with the end function (regardless of what its type is):

$lastarray = end($u);

answered Dec 1, 2011 at 18:17

Jon

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Comments

djb · Accepted Answer · 2011-12-01 18:23:58Z

0

How about $arr = array_slice($u, -1);? (will return an array containing only your desired array) Or $arr = array_pop($u)? (removes it as well)

edited Dec 1, 2011 at 18:23

answered Dec 1, 2011 at 18:17

djb

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