var str = 'internet';
performAction(function(str) {
console.log(str);
});
Is there a problem with having a private variable str and also having a callback function with a parameter of the same name?
Thanks!
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1No - just don't forget that it's not actually the same variable.Sam Dufel– Sam Dufel2011-12-10 01:14:02 +00:00Commented Dec 10, 2011 at 1:14
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2 Answers
This is just a standard scope situation - the fact that it is an anonymous function expression passed as a parameter to another function doesn't matter. Note that within your performAction() function (which you don't show) it will not have any access to the str that is the parameter of the callback function - if performAction() references str it will get the global "internet" variable (or its own local str if defined).
A function's parameters are, for scope purposes, the same as that function's local variables, which means they mask other variables of the same name from outer scope - but variables with different names can still be accessed even if defined in a wider scope.
Where it could get confusing is if you do something like this:
var str = "internet";
(function(str) {
console.log(str); // "internet"
str = "local param";
console.log(str); // "local param"
})(str);
console.log(str); // "internet"
In that case I have a function with a parameter called str but when I call it I'm passing in a different str. Note that changing str within that function only changes the local str, not the global one. They are two different variables...
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There is technically no problem with it. The function will log the str that is currently in scope (your parameter).
For obvious reasons, this is not considered a good idea. At the very least, it makes for unreadable code.